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Dogenzaka

PLATINUM USERNAME WINS
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Killing is easy once you forget the taste of sugar
LOL, usually, you can find on your textbook a link to their website. From there, you can find what they have.

I'm not looking for an online version of my textbook, I'm looking for like study materials online, like sparknotes, that use reviews, questions, etc. from official textbooks mebbe :v or even just any old study tools online.
 

Nostalgia

livin' in the past
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Here's the 2nd problem that I said I'd post a bit later.

h(y) = (y^3 - 8)(y + 2)^-3. Again, it's asking for the domain and possible zeros.

First, I worked the negative exponent to make it...

y^3 - 8
(y + 2) ^3

0 to any power will be zero, so I think it's safe to say that -2 will not work out, but all other real numbers will. As for the zero, 2^3 is 8, so that's one, and no other number would work, considering that (-2)^3 is -8. Is this correct?
 

Angel

number one fan of teresa giudice
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Here's the 2nd problem that I said I'd post a bit later.

h(y) = (y^3 - 8)(y + 2)^-3. Again, it's asking for the domain and possible zeros.

First, I worked the negative exponent to make it...

y^3 - 8
(y + 2) ^3

0 to any power will be zero, so I think it's safe to say that -2 will not work out, but all other real numbers will. As for the zero, 2^3 is 8, so that's one, and no other number would work, considering that (-2)^3 is -8. Is this correct?

y^3 - 8
(y+2)^3

y^3 - 8
(y+2)(y^2+2y+4)

y^3 - 8
y^3+4y^2+8y+8

-8
4y^2+8y+8

^in case it needed to be simplified. but yeah, y=2 is the only solution. and domain=[x=(all real numbers), (excluding) -2)
 

Nostalgia

livin' in the past
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y^3 - 8
(y+2)^3

y^3 - 8
(y+2)(y^2+2y+4)

y^3 - 8
y^3+4y^2+8y+8

-8
4y^2+8y+8

^in case it needed to be simplified. but yeah, y=2 is the only solution. and domain=[x=(all real numbers), (excluding) -2)[/QUOTE]

Thank you. It didn't ask to be simplified, but factoring it does help to confirm that -2 is to be excluded. y^3 = -8 +8 cancel and 4y^2 (or 16) and 8y (or -16) cancel as well. That helps to bring the entire thing to a close.
 

Angel

number one fan of teresa giudice
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oops, coulda simplified further.

-8
4(y^2+2y+2)

-2
y^2+2y+2
 

Reika Noko

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20. Assume that Y is the dominant allele for the yellow seeds and y is the recessive allele for green seeds. What is the probability that a pea plant with the genotype Yy crossed a pea plant with the genotype yy will have an offspring with the genotype yy?
Does it mean that it would most likely be an offspring with green seeds because the offspring's heredity would be coming from the pea plant with the genotype yy, being a recessive trait? Or am I completely wrong (since I'm not good with math that is included in science)?
 

Vayne Mechanics

Expert of Asian things
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I don't know why you're having trouble with that. The answer is 50%.
allelechart.png


You should have learned these box-like diagrams.
 

Aucune Raison

DARLING SO THERE YOU ARE
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my mind is kinda blehhh right now so i don't get what you're trying to say, but that queston is simple
you know those heredity squares? just make a square from those two genotypes, then count how many of the yy genotype there are, and the probability is that value/4

ken :-[
 

Reika Noko

Forever lurking
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I don't know why you're having trouble with that. The answer is 50%.
allelechart.png


You should have learned these box-like diagrams.
Punnett squares? Yeah suck at that too, sort of.
alright thanks.
 

Vayne Mechanics

Expert of Asian things
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How do you suck at them, it's like:

draw a square
divide it into four smaller squares
write the first genotype down the left side
write the second genotype across the top
multiply
 

stephaknee

Hakuna Matata
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okay ken this one's for you

take the indefinite integral of: x(x+4)^1/2

the answer is (2/5)(x+4)^(5/2) - (8/3)(x+4)^(3/2) + c

these are usually pretty easy but I dunno how the fuck the book got that answer.
so far all I have is that
u = x+4
du = 1

I tried having u = (x+4)^(1/2) then du be (1/2)(x+4)^(-1/2) but that doesn't seem to work either.

[edit] okay I got a little further.
u = x + 4
x = u - 4

so I have (u-4)(u)^(1/2)

stuck again!
 
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Gatorade

Naturally, we called it Gatorade
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Dogen was inspired by me and stole my idea for a homework thread which needs to be stickied.
So did you have a homework thread before me and dogen? I made mine like a month ago... no, more like 2 weeks ago. I don't remember exactly when...
 
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