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I'll post when I have a question...it's currently slipped my mind.

I thought we greatly needed something like this.

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- Thread starter Dogenzaka
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I'll post when I have a question...it's currently slipped my mind.

I thought we greatly needed something like this.

A

Can we get this stickied by someone so we don't need to bump it from time to time?

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I personally need lots of help in math, so any provided help would be great.

I'll be back when I think of a question lol.

A

here're my glasses let's get to werk! O-O

A

International History

American History

Religion (Catholicism)

Science (to a certain degree)

Math (to a certain degree)

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One of these threads exists already, but whatever. Anyway, for those of you that are interested in checking over 2 algebraic problems for me, here you go.

The first one is g(x) =

__x^3 + 2x__

x^2 - 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x^ would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

The first one is g(x) =

x^2 - 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x^ would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

Last edited:

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*clings to Social Studies and English books of sanctification*

Most of my math clumsiness comes from not remembering what I was taught. Since I became homeschooled, I admit while it is great, after I finished math, I moved on to other courses planning to pick up the succeeding course later. Therefore, I'd go long periods of time not practicing equations. I finished Alegebra and got an A in it, but I'm looking at your problem and don't remember how to start picking it apart.x^3 + 2x

x^2 + 4

That's my problem.

Can someone please step-by-step solve this problem....so I can remember how to do it?

Also what's the "^" for? I don't remember signs very well.

One of these threads exists already, but whatever. Anyway, for those of you that are interested in checking over 2 algebraic problems for me, here you go.

The first one is g(x) =

x^3 + 2x

x^2 + 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

no, domain is all real numbers. if you square a number, you're essentially ridding yourself of the negative, no matter what x is. (you're giving it an absolute value)

as for zero's, i don't think that's possible either.

lol 0 denominators are evil.

Having finished my math for a while, I haven't looked at a math problem in about 5 months.

And it shows.

*clings to Social Studies and English books of sanctification*

Most of my math clumsiness comes from not remembering what I was taught. Since I became homeschooled, I admit while it is great, after I finished math, I moved on to other courses planning to pick up the succeeding course later. Therefore, I'd go long periods of time not practicing equations. I finished Alegebra and got an A in it, but I'm looking at your problem and don't remember how to start picking it apart.

That's my problem.

Can someone please step-by-step solve this problem....so I can remember how to do it?

Also what's the "^" for? I don't remember signs very well.

^=raised to the power of.

i can simplify it, and that's pretty much it.

x+2x

-------

4

3x

---

4

(3/4)x

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if you square a number, you're essentially ridding yourself of the negative, no matter what x is. (you're giving it an absolute value)

You mean, if I take a negative number, like -8, and ^2 it, it's going to be a positive number. Right?

....I'll be back.

Lol.

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no, domain is all real numbers. if you square a number, you're essentially ridding yourself of the negative, no matter what x is. (you're giving it an absolute value)

as for zero's, i don't think that's possible either.

lol 0 denominators are evil.

You're absolutely right, but I fucked up in typing the denominator. It was x^2

You're absolutely right, but I fucked up in typing the denominator. It was x^2-4, not x^2 + 4. So, (-2)^2 and (2)^2 make it to be 4 - 4. So, with that correction, am I right?

yes, you are.

@Dogen: Exactly.

x^2=x(x) and if you multiply 2 negatives together, you can't get a negative product.

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If anyone needs help in History, or analytical essays- or even to check their spelling and grammar, that's my specialty.

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We've established ground roots.

Time to build up.

Lol!

I'm currently working on a World History assignment....I'll be back if there are any questions that I've failed to figure out.

Why hello thar bffIf anyone needs help in History, or analytical essays- or even to check their spelling and grammar, that's my specialty.

Does anyone know of any good online web tools for homework, studying, flashcards, reviews based on textbooks, etc. etc.?

Public schools usually give you papers with these links to them, but I don't know of any other than sparknotes D:

The first one is g(x) =

x^3 + 2x

x^2 - 4

It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x^ would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.

(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.

Well, the domain looks good. Also, uh, why haven't you tried x = 0? That gives you a zero without making the denominator 0 too. :\

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Well, the domain looks good. Also, uh, why haven't you tried x = 0? That gives you a zero without making the denominator 0 too. :\

mah goof.

this is true.

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Well, the domain looks good. Also, uh, why haven't you tried x = 0? That gives you a zero without making the denominator 0 too. :\

Good point. I completely missed that. Thanks.

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