One of these threads exists already, but whatever. Anyway, for those of you that are interested in checking over 2 algebraic problems for me, here you go.
The first one is g(x) =
x^3 + 2x
x^2 - 4
It asks for the Domain and possible (if any) zeros of the function. My answer for the domain is all real numbers except for 2 and -2 because either of them would make 4 -4, creating a 0 denominator, which is evil. As for the zeros, I have that there aren't any zeros because assuming you factor the top to be x(x^2 + 2) any value for x^ would be positive. Even if you go with the original x^3 and give x's value a negative number to make the whole thing negative, it'll then make the original 2x negative, so it seems to be impossible to make the numerator equal 0 in any way.
(I'll type the 2nd one later). I appreciate the effort, especially considering it's a bit long to work out.