It's not that. She just never taught us it.
A 755 N diver drops from a board 10.0 m above the water's surface.
a) Find the diver's speed 5.00 m above the water's surface.
b) Find the diver's speed just before striking the water.
c) If the diver leaves the board with an initial upward speed of 2.00 m/2, find the diver's speed when striking the water.
I need to do good on this take home to boost my average. It's a 85.
To answer part c) - I'm assuming you meant to type "...upward speed of 2.00m/s..."
We're given: vi = 2.00m/s, a=acceleration due to gravity (denoted g) = -9.8 m/s^2 and d = -10.0m
[Note: g and d are negative because they are "downward" and I'm using "upward" as postive]
Let's find out high the diver jumps.
So, set vf^2 = 0 and solve for h (when he's at his maximum height, he has no vertical speed).
0 = vi^2 +2gh
h = -(vi^2) / 2g
= -(4.00m^2/s^2) / 2*(-9.8m/s^2)
Here, check your units to make sure your equation was manipulated properly. We have m^2/s^2 on top and m/s^2 on bottom. One of the m on the bottom will cancel on on the top, and the s^2 on the bottom cancels the one on top, leaving just m. Yay!
h = 0.204m
So we can add this to the initial 10.0m and get 10.204m. Why do this? Because he now has no initial vertical speed, and only acceleration due to gravity.
vf^2 = vi^2 +2gd
vf^2 = 0 + 2 (-9.8m/s^2) (-10.204m)
vf^2 = 2.0x10^2 m^2
vf = 14.1m
This question doesn't necessarily refer to homework, but it pertains to math. I've never learned percentiles, and I'd like to assume that they work similarly to percentages, but I don't know for sure.
Anyway, under the assumption that my class rank is 43 out 214, I subtracted it from the total to get 171. Then, I set up the proportion, divided 214 by 17,100 and came up with 79.91 approximately. Is that my percentile?
43/214 x 100% = 20.1%. That means you're in the top 20.1% of your class. A percentile refers to (in this case) the number of people below you. Which, as you calculated, is 79.9%.