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- Thread starter Dogenzaka
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D being diameter, R for radius and ^ meaning an exponent

you're welcome

Diameter: radius X 2

Circumference: pi multiplied by diameter

Have fun

no they want me to find the radius and diameter not the circumference and area

Aight buddy boy let me walk you through this step-by-step

1) Circumference = 264 ft.

Circumference = Pi X Diameter

Circumference/Pi = Diameter

Circumference divided by Pi will give you the Diameter. Divide that by 2 and you will get the radius.

Seeing it now?

okay thank you batman. I get it now.

If you need help with the rest, drop me a VM B)

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Which inequality describes all of the possible values for

choices:

i don't know how a is possible, c would have to be 40, max, and that yield 2(40) + 8 = 88, which isn't obtuse. d would have to be 87 min which would be 2(87) + 8 = 182, which is way more than what <FGD is in diagram.

b could, for example, be 50. 2(50) + 8 = 108. reasonable. i'd say b

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alright cool, good looks man.

that means thanks

that means thanks

An obtuse angle is an angle greater than 90 degrees. All angles are smaller than 180 degrees (because then it's just a straight line). So now we have two inequalities.

2(a) + 8 > 90

2(a) + 8 < 180

So now you just solve like a normal equation! Start off by subtracting 8 from both sides:

2(a) > 82

2(a) < 172

Now divide by 2!

a > 41

a < 86

EDIT: Ignore this. I solved it on my own.

Last edited:

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So we just got to work in my mechanics class.

Please let me know if I have this down straight:

- Kinetic Energy is (m(v)^2)/2, and the NET Kinetic Energy = the different kinetic energies for different velocities added up together.

- The Work of ANY force can be calculated by the integral of the force vector dotted with dr (r being the displacement vector). This can then be simplified to Work of ANY force = integral (from x1 to x2) of Fx dx + integral (from y1 to y2) of Fy dy.

- The Work Energy Theorem states that the TOTAL NET WORK of a system = the change in Kinetic Energy. So Wnet = (m(vf)^2)/2) - (m(vi)^2)/2). Also, Wnet = W1 + W2 + W3, so in other words, all those integrals calculated from the individual forces' components as stated above added together.

- If a force is constant, W of that force can otherwise be stated to equal F * d * cos(theta), with d being distance and theta being the angle between the two.

- If the force is perpendicular to the displacement, its Work = 0.

- I may not be remembering this right, but if the force is antiparallel to the displacement, the Work is negative, and if the force is parallel to displacement, the Work is positive?

-To find the velocities of any of simple, falling block on an inclined plane problem, I can simply make free-body diagrams, calculate the work, and then discover the velocities.

Am I getting this right?

Yep dogen, all of your statements are true.

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You can't calculate a double integral of e^y^3 dydx from x=0 to 1 and y=sqrt(x) to 1 with a normal function, can you?

It's part of my assignment but I have no idea how the bonk to integrate e^y^3

EDIT: Never mind, I reverse the order of integration by changing the limits.

It's part of my assignment but I have no idea how the bonk to integrate e^y^3

EDIT: Never mind, I reverse the order of integration by changing the limits.

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We're doing reactions in chemistry and I don't understand what does adding heat do?

Like this: heat + NaOH ----> ?

Also, he wants us to write what kind of reaction it is. Would I just write "heat"?

EDIT: I think I figured it out. Is it a decomposition reaction?

Like this: heat + NaOH ----> ?

Also, he wants us to write what kind of reaction it is. Would I just write "heat"?

EDIT: I think I figured it out. Is it a decomposition reaction?

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D

The product would depend on the other reactant(s) aside from heat in the formula.

For your specific example check: Sodium hydroxide - Wikipedia, the free encyclopedia

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Are you missing a catalyst?

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